Fundamentals of Differentiation

$k=12$

$k=-4$

$k=4$

$k=-12$

$\frac{dw}{dv}=\frac{w}{e}$

$\frac{dw}{dv}=\frac{e}{w}$

$\frac{dw}{dv}=\frac{ev^2}{w^3}$

$\frac{dw}{dv}=\frac{v}{e}$

$f'(c)=\frac{\tan^2(c)\cdot\cos(c)}{\sin(c)\cdot\sin(c)}$

$f'(c)=\frac{\sec(c)\cdot\cos(c)}{\sin^2(c)}$

$f'(c)=\frac{\tan(c)\cdot\cos(c)}{\sin(c)\cdot\sin(c)}$

$f'(c)=\frac{-\tan(c)\cdot\cos(c)}{\sin(c)}$

$\frac{4x^3 + 3x^2}{(2x + 1)^2}$

$\frac{6x^3 + 3x^2}{(2x + 1)^2}$

$\frac{4x^3 + 3x^2}{x^6}$

$\frac{x^3 - 1}{(2x + 1)^2}$

$-\frac{x^2 - 2x - 1}{(x^3 + x^2 + x + 1)^2}$

$-\frac{x^2 - 2x - 1}{(x^2 + 1)^2}$

$\frac{x^2 - 1}{x^3 + x^2 + x + 1}$

$\frac{x^2 - 2x - 1}{(x^2 + 1)^2}$

$-\frac{524288}{\pi^2}$

$-\frac{108576}{i}$

$\frac{104857}{\pi}$

$-\frac{524288}{\pi}$

$p'(c) = -\frac{q'(c)}{\ln(c)}$

$p'(c) = \frac{q(c)}{c}$

$p'(c) = cq'(c)$

$p'(c) = -cq'(c)$

$\frac{4(3-x)}{(2-x)^3}$

$\frac{8(2+x)}{(2-x)^3}$

$\frac{-12}{(2-x)^4}$

$\frac{-8}{(2-x)^3}$

$\frac{4e^x \cdot x^3 - 12e^x \cdot x^2 + e^x \cdot x - e^x}{(4x^3 + x)^2}$

$\frac{4e^x \cdot x^3 - 12e^x \cdot x^2 + e^x \cdot x - e^x}{4x^3 + x}$

$\frac{4e^x \cdot x^3 - 12e^x \cdot x^2 + e^x \cdot x - e^x}{e^x}$

$\frac{4x^3 - 12e^x \cdot x^2 + e^x \cdot x - e^x}{(4x^3 + x)^2}$

$\frac{-3x^2 - 4x - 3}{(x - 1)^2}$

$\frac{-3x^2 + 4x - 3}{(x^2 - 1)^2}$

$\frac{-3x^2 - 4x + 3}{(x^2 - 1)^2}$

$\frac{-3x^2 - 4x - 3}{(x^2 - 1)^2}$